Last year's garden had a length of 4 meters. This year, Mr. Petersen plans a garden three times as long and two times as wide, resulting in dimensions of 12 meters by 10 meters.
To find the length of Mr. Petersen's garden last year, we can use the area formula for a rectangle, which is length multiplied by width. Given that the width is 5 meters and the area is 20 square meters, we can set up the equation:
Area = Length * Width
20 = Length * 5
Solving for the length:
Length = 20 / 5 = 4 meters
Therefore, last year's garden had a length of 4 meters.
For this year's garden, Mr. Petersen wants to make it three times as long and two times as wide. If we denote the length of this year's garden as L' and the width as W', we have:
L' = 3 * 4 = 12 meters
W' = 2 * 5 = 10 meters
So, this year's garden has a length of 12 meters and a width of 10 meters.
In summary, last year's garden had a length of 4 meters. This year, Mr. Petersen plans to make the garden three times as long and two times as wide, resulting in a garden with dimensions of 12 meters by 10 meters.
The question probable may be:
Last year, Mr. Petersen's rectangular garden had a width of 5 meters and an area of 20 square meters. This year, he wants to make the garden three times as long and two times as wide.
a. Solve for the length of last year's garden using the area formula. Then, draw and label the measurements of this year's garden