Final answer:
The statement is false and a counterexample can be given to disprove it.
Step-by-step explanation:
The statement is false and a counterexample can be given to disprove it.
Counterexample: Let's consider the functions f(x) = 1/x and g(x) = 1/(x^2).
Clearly, f(x) ≤ g(x) for all x greater than 1.
Now, ∫1∞ g(x) dx = ∫1∞ 1/(x^2) dx. This integral converges as it is a p-series with p = 2 and p > 1.
However, ∫1∞ f(x) dx = ∫1∞ 1/x dx. This integral diverges as it is a p-series with p = 1 and p ≤ 1.
Therefore, the statement is false and the given counterexample disproves it.