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Solve the equation of the axis of symmetry of the following p y=-2x²+16

User Zelid
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1 Answer

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Final answer:

The equation of the axis of symmetry is x = 0.

Step-by-step explanation:

The equation represents a quadratic function in the form y = ax^2 + bx + c. To find the axis of symmetry, we can use the formula x = -b/2a.

Given the equation y = -2x^2 + 16, we can see that a = -2 and b = 0. Plugging these values into the formula, we get x = -0/2(-2), which simplifies to x = 0.

Therefore, the equation of the axis of symmetry is x = 0.

User Ppotaczek
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