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Given kite ABCD where AN=3.8m,BN=2.1m what is BC ? Round to the nearest tenth.

User Musso
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1 Answer

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Using the Pythagorean Theorem with BN = 2.1m and CD = BN in kite ABCD, BC is approximately 4.34 meters, rounded to the nearest tenth.

To find the length of BC in the kite ABCD, you can use the Pythagorean Theorem. In a kite, the two pairs of consecutive sides are equal in length. Let's consider triangle BCD.

BC is one leg, and BN and CD are the other two sides. According to the Pythagorean Theorem:

BC^2 = BN^2 + CD^2

Given that BN = 2.1m and CD = BN (since opposite sides in a kite are equal), you can substitute these values into the equation:

BC^2 = (2.1)^2 + (3.8)^2

BC^2 = 4.41 + 14.44

BC^2 = 18.85

Now, take the square root of both sides to solve for BC:

BC = √(18.85)

BC ≈ 4.34

So, the length of BC is approximately 4.34 meters when rounded to the nearest tenth.

User Ander
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