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Solve ,
I=∫₀π/4 ¹44(x) tan ³2(x) d x=∫ₐ ᵇ uᵖ(1+u²)ᑫ d u ,

User Spell
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1 Answer

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Final answer:

To solve the given equation, we need to apply the correct trigonometric substitution and simplify the integral. The integral can be rewritten using the identity tan^2(x) = sec^2(x) - 1 and then applying the substitution u = tan(x) and du = sec^2(x) dx. Finally, we determine the limits of integration by substituting the original limits in terms of x into the equation u = tan(x).

Step-by-step explanation:

To solve the equation:

I = ∫0π/4 44(x) tan2(x) dx = ∫ab up(1+u2)ᵢ du

we need to apply the correct trigonometric substitution. Let's start by simplifying the integral:

I = ∫0π/4 44(x) tan3(x) dx

Using the identity tan2(x) = sec2(x) - 1, we can rewrite the integral as:

I = ∫0π/4 44(x) (sec2(x) - 1) tan(x) dx

Now, we can let u = tan(x), and du = sec2(x) dx:

I = ∫0π/4 44(u) (u2 - 1) du

The next step is to determine the limits of integration a and b, which depend on the original limits of integration in terms of x. Since the original limits are from 0 to π/4, we can substitute x = 0 and x = π/4 into the equation u = tan(x) to find the corresponding values of u. The limits of integration become a = tan(0) and b = tan(π/4):

a = tan(0) = 0

b = tan(π/4) = 1

Now, we can rewrite the integral again:


I = ∫ab up(1+u2)ᵢ du

User Aniketh Saha
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