Final answer:
The equation x⁵ydy + 5dy = 0 is not linear or exact, but it is separable because the variables x and y can be moved to opposite sides of the equation.
Step-by-step explanation:
You are tasked with classifying the equation x⁵ydy + 5dy = 0 as separable, linear, exact, or none of these. This type of problem is common in differential equations, a topic covered in advanced high school or college mathematics courses. To classify the equation, you need to recognize the form of the differential equation and apply the definitions of separable, linear, and exact equations.
This given equation is not linear because a linear equation has the form y = mx + b or alternatively the differential form dy/dx + P(x)y = Q(x), where P(x) and Q(x) are functions of x only, and y does not appear in any products or powers.
The equation also does not fit the definition of an exact equation, which is of the form M(x, y)dx + N(x, y)dy = 0, where ∂M/∂y = ∂N/∂x. However, the given equation can be classified as separable because it can be rewritten in the form (ydx + 5dx) / x⁵y = -dy/y, where the variables x and y can be separated onto opposite sides of the equation.