89.7k views
3 votes
Consider the integrals.

[ I=∫₀² πsin ²(x) d x; J=∫₀² πcos ²(x) d x ]
Plot the graphs corresponding to the integrals.

1 Answer

1 vote

Final answer:

To plot the graphs corresponding to the integrals, we need to evaluate the integrals I and J. The integral I is calculated as the area under the curve of sin^2(x) between x=0 and x=2. The integral J is calculated in a similar manner, but using the function cos^2(x) instead.

Step-by-step explanation:

To plot the graphs corresponding to the integrals, we first need to evaluate the integrals I = ∫02 πsin²(x)dx and J = ∫02 πcos²(x)dx. Let's start with I:

We know that ∫02 sin²(x)dx is equal to the area under the curve of sin²(x) between x=0 and x=2. To evaluate this integral, we can use the geometric interpretation of the integral as the area under the curve.

If we plot the function y = sin²(x), we can observe that the curve is a half-period of a sine wave, bounded between the x-axis and the curve. Therefore, the area under the curve can be divided into smaller rectangles with widths dx and heights sin²(x).

A similar approach can be used to evaluate J, which is the integral ∫02 πcos²(x)dx. However, this time the function is y = cos²(x), and the area under the curve represents the integral J.

User Malificent
by
7.9k points

Related questions

asked Apr 3, 2024 71.5k views
Gdso asked Apr 3, 2024
by Gdso
8.3k points
1 answer
1 vote
71.5k views