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Among the 17 students of the group, of which 8 are girls, 7 tickets to the theater are raffled off. What is the probability that there will be 4 girls and 3 boys among the ticket holders?

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Final answer:

To find the probability of having 4 girls and 3 boys among the ticket holders, we can use the hypergeometric distribution. By substituting the values into the formula, the probability is calculated to be 0.152 or 15.2%.

Step-by-step explanation:

To find the probability that there will be 4 girls and 3 boys among the ticket holders, we need to use the hypergeometric distribution. The group of interest is the 17 students in the group, and the sample is the 7 tickets being raffled off.

The probability can be calculated using the formula:

P(X = k) = (C(n, k) * C(N-n, r-k)) / C(N, r)

Where:

P(X = k) is the probability of getting k girls and r-k boys,

C(n, k) is the combination of choosing k girls from n,

C(N-n, r-k) is the combination of choosing r-k boys from N-n,

C(N, r) is the combination of choosing r tickets from N, which is 17 in this case.

By substituting the given values, we have:

P(X = 4) = (C(8, 4) * C(17-8, 7-4)) / C(17, 7) = (70 * 42) / 19448 = 0.152

Therefore, the probability that there will be 4 girls and 3 boys among the ticket holders is 0.152 or 15.2%.

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