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Find the derivative of y(theta) = cosh^−1(sec(theta)), 0 ≤ theta < /2
y ′(theta) =

User Durtal
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1 Answer

5 votes

Final answer:

The student's question requires using the chain rule and the derivatives of inverse hyperbolic functions along with trigonometric identities to find the derivative of y(θ) = cosh^−1(sec(θ)).

Step-by-step explanation:

The student has asked to find the derivative of the function y(θ) = cosh−1(sec(θ)), where 0 ≤ θ < π/2. To find y'(θ), we can use the chain rule and the derivatives of inverse hyperbolic functions in conjunction with trigonometric identities. However, the provided information does not directly apply to the problem, so we need to derive the expression using the known derivatives and rules of differentiation.

User Dan Breen
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