Final answer:
The value of c for which the integral from 6 to infinity of c/x⁴ dx equals 1 is c = 108.
Step-by-step explanation:
The question asks for the value of c for which the integral from 6 to infinity of c/x⁴ dx equals 1. To find this value, we will perform the integration and solve for c.
First, we integrate:
- ∫(inf) c/x⁴ dx = c ∫(inf) x⁻⁴ dx
- = c [-1/(3x³)]⁶(inf)
- = c [0 - (-1/(3×6³))] = c/(3×6)
Now, we set the result equal to 1 and solve for c:
c/(3×6) = 1
c = 3×6
Thus, c = 108 is the value for which the given integral equals 1.