Question

Triangles ABD and ACE are similar right triangles. Which best describes how to find the equation of the line? (BD)/(DA)=(CE)/(EA) so (4)/(2)=(y-3)/(x-2); solve for y to get y=2x-1 (DA)/(BD)=(EA)/(CE) so (2)/(4)=(x-2)/(y); solve for y to get y=2x-4. (BD)/(DA)=(CE)/(EA) so (4)/(2)=(y-3)/(x); solve for y to get y=2x+3.

Answer 1

To find the equation of the line for similar triangles ABD and ACE, we can use proportional sides. The equation is y = 2x - 1.

Step-by-step explanation:

Triangles ABD and ACE are similar right triangles. To find the equation of the line, we can use the fact that similar triangles have proportional sides. Since (BD)/(DA) = (CE)/(EA), we can set up an equation using these ratios. Let's solve for y in the equation (4)/(2) = (y-3)/(x-2).

Simplify the equation to get (2)/(1) = (y-3)/(x-2).

Cross-multiply to get 2(x-2) = 1(y-3).

Distribute and simplify further to get 2x - 4 = y - 3.

Finally, isolate y by adding 3 to both sides to get y = 2x - 1.