Question

h(t)=-16t²+16t+5 gives the height of a ball, in feet, t seconds after it is tossed. What is the average rate of change, in feet per second, over the interval 0.25,0.50 ? If needed, round your answer to the nearest hundredth (2 decimals ).

Answer 1

To find the average rate of change, calculate the change in height and divide by the change in time.

Step-by-step explanation:

The average rate of change represents the average velocity of the ball over the given time interval. To calculate it, we need to find the change in height and divide it by the change in time.

At t = 0.25 seconds, the height of the ball is h(0.25) = -16(0.25)² + 16(0.25) + 5. Calculate this value. Then, at t = 0.50 seconds, calculate the height h(0.50) using the same equation.

Finally, subtract the two heights and divide by the change in time (0.50 - 0.25 = 0.25 seconds) to find the average rate of change, rounded to the nearest hundredth.