Question

Let p=x²-7. Which equation is equivalent to (x²-7)²-4x²+28=5 in terms of p ?

Answer 1

To express the equation (x²-7)²-4x²+28=5 in terms of p, we substitute x²-7 with p, resulting in the equivalent equation p² - 4p + 28 = 5.

Step-by-step explanation:

The student has provided the expression (x²-7)²-4x²+28 and defined p as x²-7. To express the given equation in terms of p, we can substitute x²-7 with p into the equation. Therefore, the equivalent equation in terms of p would be p² - 4(x²-7) + 28 = 5. Simplifying further, we can replace every x²-7 with p, getting the final equation p² - 4p + 28 = 5.