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What are the three factors of (x³-3x²-4x+12)-:(x+2) ?

User Petrumo
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Final answer:

To find the factors of the expression (x³-3x²-4x+12)-:(x+2), perform polynomial division and repeat until the remainder is zero.

Step-by-step explanation:

To find the factors of the expression (x³-3x²-4x+12)-:(x+2), we need to perform polynomial division.

Step 1: Divide x³ by x to get x².

Step 2: Multiply (x+2) by x² to get x³+2x².

Step 3: Subtract x³+2x² from x³-3x²-4x+12 to get -5x²-4x+12.

Step 4: Repeat steps 1-3 with -5x²-4x+12 until the remainder is zero.

The three factors of (x³-3x²-4x+12)-:(x+2) are (x²-5), (-4x-2), and 0.

User Buzu
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