Final answer:
The length of the polar curve given by r = 10e^(0.5θ) on the interval 0 ≤ θ ≤ 1/6 is approximately 48.2 units.
Step-by-step explanation:
The length of a polar curve can be found using the following formula:
length = ∫√(r^2 + (dr/dθ)^2) dθ
In this case, we have r = 10e^(0.5θ).
Using this formula, we can find the length of the polar curve on the interval 0 ≤ θ ≤ 1/6:
length = ∫√(100e^θ + 25e^θ) dθ
= ∫√(125e^θ) dθ
= ∫√(5^3e^θ) dθ
Using the power rule of integration, we can find the antiderivative:
= 2/3 * (5^3/2 * e^(θ/2)) + C
= 2/3 * 125^(3/2) * e^(1/12) - 2/3 * 125^(3/2)
Now, we can evaluate the length on the given interval:
length = 2/3 * 125^(3/2) * e^(1/12) - 2/3 * 125^(3/2)
length ≈ 48.2 units.