134k views
4 votes
Solve, for 0
(sin2x+sinx)/(cos2x+cosx+1)=2cosx , aswers to 3 decimal places.

User Robin Huy
by
8.9k points

1 Answer

4 votes

Final answer:

To solve the given equation, simplify the expression and use the trigonometric identity to substitute for the cosine terms. Then, solve the resulting quadratic equation for x.

Step-by-step explanation:

To solve the equation (sin2x+sinx)/(cos2x+cosx+1)=2cosx, we can start by simplifying the expression. First, multiply both sides of the equation by the denominator (cos2x+cosx+1) to get rid of the fraction. This gives us sin2x+sinx=2cosx*(cos2x+cosx+1). Next, distribute the 2cosx into the parentheses on the right side of the equation. After simplifying and rearranging the terms, we can use the trigonometric identity tan(x) = sin(x)/cos(x) to substitute for the cosine terms. Solving the resulting quadratic equation will give the values of x.

User Kenny Yap
by
8.2k points