Final answer:
The vertex of the quadratic function f(x) = x² - 10x + 17 is at the point (5, f(5)).
Step-by-step explanation:
The vertex of a quadratic function can be found using the formula:
x = -b/(2a)
where a and b are the coefficients of the quadratic function. For the function f(x) = x² - 10x + 17, the coefficient of x² is 1, and the coefficient of x is -10. Plugging these values into the formula, we get:
x = -(-10)/(2*1) = 10/2 = 5
Therefore, the vertex of the function is at the point (5, f(5)).