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Suppose f(x) and f(4) have the values shown. Let y³ +[f(x)]³=6 x y+326 . Find y(2) at (3,1)

User Moak
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1 Answer

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Final answer:

To find y(2) at (3,1), substitute x = 3 and y = 1 into the given equation. By solving for f(3), we can determine that y(2) = f(3) = 271.

Step-by-step explanation:

To find y(2) at (3,1), we need to substitute x = 3 and y = 1 into the given equation:

y³ + [f(x)]³ = 6xy + 326

(1)³ + [f(3)]³ = 6(3)(1) + 326

1 + [f(3)]³ = 18 + 326

[f(3)]³ = 345

Since we know that f(4) = 74, we can write [f(3)] as follows:

[f(3)] = [f(4) - (f(4) - f(3))]

Plugging in the values, we get:

[f(3)] = 74 - (74 - f(3))

345 = 74 - (74 - f(3))

f(3) = 345 - 74

f(3) = 271

Therefore, y(2) = f(3) = 271.

User Nirav Kamani
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