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A circle has the equation 2(x-2)²+2y²=2
(a) Find the center ( h,k) and radius r of the circle

User Benyi
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1 Answer

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Final answer:

The center of the circle is (2, 0) and the radius is 1. This was determined by comparing the given circle equation with the general form of a circle's equation and simplifying.

Step-by-step explanation:

The equation of the circle is given as 2(x-2)²+2y²=2. To find the center (h, k) and the radius (r) of the circle, we can first simplify the equation by dividing every term by 2 to remove the coefficient on the left side of the equation.

The simplified equation is (x-2)²+y²=1. Now, the general form of a circle's equation is (x-h)²+(y-k)²=r², where (h, k) is the center and r is the radius of the circle.

Comparing the simplified equation with the general form, we identify h=2, k=0, and r²=1. Therefore, the center of the circle is (2, 0) and the radius is 1.

User Remco Bakker
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