Final Answer:
The parabola reflected over the x-axis, shifted 11 units up, and 6 units right can be represented by the equation y = a(x - 6)² + 11, where
is the coefficient determining the direction of the reflection.
Step-by-step explanation:
To create a parabola reflected over the x-axis, we use the general form y = a(x - h)² + k, where (h, k) represents the vertex of the parabola. In this case, the vertex is shifted 6 units to the right and 11 units up, so h = 6 and k = 11. Therefore, our equation becomes y = a(x - 6)² + 11.
The reflection over the x-axis is achieved by changing the sign of the
coefficient. If the original parabola opens upward, the reflected parabola will open downward, and vice versa. Since the direction of reflection is not specified, we assume a reflection over the x-axis. Therefore, the final equation is
, where
determines the steepness and direction of the parabola.
In summary, the parabola reflected over the x-axis, shifted 11 units up, and 6 units right is represented by y = a(x - 6)² + 11, where
determines the direction of the reflection. This equation provides a clear and concise expression for the given transformation of the original parabola.