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The integral ∫ dx/ x²( x⁴+ 1) ³/⁴ equals

User Birju
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Final answer:

To solve the integral ∫ dx/ x²( x⁴+ 1) ³/⁴, we can use a substitution. Let u = x⁴ + 1, then differentiate both sides to find du = 4x³ dx. Rearranging, we have dx = du / (4x³). Substituting these values back into the integral, we simplify it to (1/4) ∫ du / (x² * (x⁴ + 1)^(³/⁴)).

Step-by-step explanation:

Integral of ∫ dx/ x²( x⁴+ 1) ³/⁴

To solve this integral, we can use a substitution. Let u = x⁴ + 1, then differentiate both sides to find du = 4x³ dx. Rearranging, we have dx = du / (4x³). Substituting these values back into the integral, we get:

∫ dx/ x²( x⁴+ 1) ³/⁴ = ∫ du / (x² * u^(³/⁴)) = (1/4) ∫ du / (x² * u^(³/⁴))

Now, notice that the integral on the right side is easier to solve. Let's simplify it further:

(1/4) ∫ du / (x² * u^(³/⁴)) = (1/4) ∫ du / (x² * (x⁴ + 1)^(³/⁴))

This is the final answer to the integral.

User TheQ
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