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Find the zeros for funct 5. g(x)=x²-11x+18

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Final answer:

To find the zeros of the function g(x) = x²-11x+18, the quadratic equation x²-11x+18 = 0 needs to be solved. Using the quadratic formula, the solutions are x = 9 and x = 2.

Step-by-step explanation:

To find the zeros of the function g(x) = x²-11x+18, we need to solve the quadratic equation x²-11x+18 = 0. We can do this by factoring or by using the quadratic formula. Let's use the latter method:

The quadratic formula states that for an equation of the form ax²+bx+c = 0, the solutions are given by:

x = (-b ± √(b²-4ac))/(2a)

In our equation, a = 1, b = -11, and c = 18. Plugging in these values into the formula, we get:

x = (-(-11) ± √((-11)²-4(1)(18)))/(2(1))

Simplifying further, we have:

x = (11 ± √(121-72))/(2)

x = (11 ± √49)/(2)

x = (11 ± 7)/(2)

So the zeros of the function are x = 9 and x = 2.

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