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Find the equation of a line that is perpendicular to f(x)=−5x−7 and passes through the point (2, 3):

User Chris Ladd
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Final answer:

The equation of the line that is perpendicular to f(x) = -5x - 7 and passes through (2, 3) is y = 1/5x + 13/5.

Step-by-step explanation:

The question asks us to find the equation of a line that is perpendicular to the given line f(x) = -5x - 7 and passes through the point (2, 3).

First, we determine the slope of the given line. Since the slope of f(x) is -5, the slope of a line perpendicular to it will be the negative reciprocal. Therefore, the slope of the line we are trying to find is 1/5.

Next, we use the point-slope form of the line equation y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point the line passes through. Substituting the slope and point (2, 3), we get:

y - 3 = 1/5(x - 2)

After simplifying, we find the equation of the line:

y - 3 = 1/5x - 2/5

y = 1/5x + 13/5

User Mamun
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