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Find the limit: limᵗ→¹ ((t²-1)/(t-1) i + (1)/(t²-1) j + (sinπt)/(lnt) k).

User Efik
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1 Answer

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Final answer:

The limit of the given expression as t approaches 1 is (1)i + ∞j + sinπk.

Step-by-step explanation:

To find the limit of the given expression, we can evaluate the limit of each component separately. Let's start with the i-component:

limᵗ→¹ (t²-1)/(t-1) = limᵗ→¹ (t+1) = 1.

Next, for the j-component:

limᵗ→¹ (1)/(t²-1) = limᵗ→¹ (1)/((t+1)(t-1)) = ∞.

Finally, for the k-component:

limᵗ→¹ (sinπt)/(lnt) = sinπ.

Therefore, the limit of the given expression as t approaches 1 is (1)i + ∞j + sinπk.

User Mahmoud Elgohary
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