Final answer:
To compute the double integral over the rectangle R={(x,y)∣−1≤x≤1,1≤y≤2} of the function f(x,y) = x^2 * y + 2, we integrate the function over the given region R and find the result to be 2/3.
Step-by-step explanation:
To compute the double integral over the rectangle R={(x,y)∣−1≤x≤1,1≤y≤2} of the function f(x,y) = x^2 * y + 2, we need to integrate the function over the given region R.
Step 1: Set up the integral:
∬R(x^2 * y + 2) dA where R is the region defined by -1≤x≤1 and 1≤y≤2.
Step 2: Perform the integration:
∫-11 ∫12 (x^2 * y + 2) dy dx
= ∫-11 [(1/2)x^2 * y^2 + 2y] from 1 to 2 dx
= ∫-11 [(1/2)x^2 * (2^2) + 2(2)] - [(1/2)x^2 * (1^2) + 2(1)] dx
= ∫-11 2x^2 + 10 dx
= [x^3/3 + 10x] from -1 to 1
= [(1/3) + 10(1)] - [(-1/3) + 10(-1)]
= (1/3 + 10) - (-1/3 + 10)
= 1/3 + 10 + 1/3 - 10
= 2/3