80.4k views
2 votes
The length of time (in minutes) spent waiting in line at a certain bank is modeled by the exponential probability density function

f(t) = { ce-ct if t ≥ 0
0 if t < 0
where c is a constant.The mean wait time is 8 minutes.
(a) What is c?
(b) What is the probability that a customer will have to wait more than 10 minutes?

1 Answer

4 votes

Final answer:

To find the constant c for the exponential probability density function with a mean wait time of 8 minutes, we use the formula 1/c = mean, resulting in c = 1/8. The probability of waiting more than 10 minutes is found using the CDF of the exponential distribution, resulting in P(T > 10) = e^(-10/8).

Step-by-step explanation:

The student's question pertains to finding the constant c in the exponential probability density function for the wait time at a bank, and then using it to calculate the probability of a customer waiting more than 10 minutes. Given that the mean wait time is 8 minutes, the value of c can be determined using the relationship between the mean and the rate parameter in an exponential distribution, which is mean = 1/c. Therefore, c = 1/8.

To find the probability that a customer will have to wait more than 10 minutes, we use the cumulative distribution function (CDF) of the exponential distribution, which, for a wait time t, is given by 1 - e-ct. The probability of waiting more than 10 minutes is thus P(T > 10) = 1 - P(T ≤ 10) = 1 - (1 - e-(1/8)×10) = e-10/8.

User Shinnc
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories