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Hooke's Law for springs states that the amount of force required to hold a spring that is compressed (or extended) to a particular length is proportionate to the distance the spring is compressed (or extended) from its natural length. That is, the force to compress (or extend) a spring `x units from its natural length is `F(x) = kx for some constant "k". A force of "30 \"lb"` is required to stretch a spring from its natural length of `1 \ "ft" to a length of `15\ "in". How much work is done in stretching the spring from `1 \ "ft" to "21 \ "in"? 'W = _______

User J Evans
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Final answer:

Hooke's Law states that the force required to hold a spring compressed or extended is proportional to the distance it is compressed or extended. To find the work done in stretching a spring, we need to calculate the change in length and use the formula W = (1/2)kx^2. In this problem, the given force and length values can be used to find the constant k and then calculate the work done.

Step-by-step explanation:

Hooke's Law states that the force required to hold a spring compressed or extended to a certain length is proportional to the distance it is compressed or extended. The force to compress or extend a spring x units is given by F(x) = kx, where k is a constant.

In this question, a force of 30 lb is required to stretch a spring from its natural length of 1 ft to a length of 15 in. To find the work done in stretching the spring from 1 ft to 21 in, we need to calculate the change in length and use the formula W = (1/2)kx^2.

First, convert the lengths to the same unit. 15 in is 1.25 ft, and 21 in is 1.75 ft. The change in length is 1.75 ft - 1 ft = 0.75 ft. To find k, we can use the given information that F = 30 lb when x = 1.25 ft. Substitute these values into the formula F = kx and solve for k.

Once k is found, plug it into the formula W = (1/2)kx^2, with x = 0.75 ft, to calculate the work done.

User Dgnorton
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