Question

A ball is thrown into the air with an initial upward velocity of 60f(t)/(s). Its height (h) in feet after t seconds is given by the function h=-16t^(2)+60t+6. What will the height be at t=3 seconds?

Answer 1

To find the height of the ball at t=3 seconds, plug 3 into the quadratic equation h = -16t^2 + 60t + 6, which calculates to a height of 42 feet.

Step-by-step explanation:

The question asks for the height of a ball at a specific time given a quadratic equation that represents its vertical motion. To find the height of the ball at t=3 seconds, we simply substitute 3 for t in the equation h = -16t2 + 60t + 6:

h(3) = -16(3)2 + 60(3) + 6

h(3) = -16(9) + 180 + 6

h(3) = -144 + 180 + 6

h(3) = 42 feet

So the height of the ball at t=3 seconds is 42 feet.