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Find the absolute maximum and absolute minimum values of f on each interval.

f(x) =5x2 − 100x + 750
(a) [ 4, 14 ]
Absolute maximum:
Absolute minimum:

User Jdl
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1 Answer

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Final answer:

To find the absolute maximum and minimum of f(x) = 5x^2 - 100x + 750 on the interval [4, 14], we found the derivative, identified the critical point at x = 10, and evaluated the function at x = 10, 4, and 14. The absolute maximum value is 490 at x = 14, and the absolute minimum value is 250 at x = 10.

Step-by-step explanation:

To find the absolute maximum and absolute minimum values of the function f(x) =5x2 − 100x + 750 on the interval [4, 14], we must consider both the critical points of the function within this interval and the values of the function at the endpoints of the interval.

Step 1: Find the derivative of the function

First, we find the derivative of the function, f'(x), to determine the critical points.


f'(x) = 10x - 100

Step 2: Solve for critical points

Next, we solve the equation f'(x) = 0 to find the critical points within the interval.


10x - 100 = 0
x = 10

Step 3: Evaluate the function at the critical point and endpoints

We then evaluate f(x) at x = 10, as well as at the endpoints of the interval, x = 4 and x = 14.

f(4) = 5(4)2 - 100(4) + 750 = 390
f(10) = 5(10)2 - 100(10) + 750 = 250
f(14) = 5(14)2 - 100(14) + 750 = 490

Absolute Maximum and Minimum

The absolute maximum value of f(x) on the interval [4, 14] is 490 at x = 14. The absolute minimum value is 250 at x = 10.

User Cemal Okten
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7.7k points