Question

Find the derivative of the two functions and show that the derivative equals zero when the derivative of the other is zero. Demonstrating they are the same equation that you out the value for actually causes you to be able to have two equals zero.

a. d(x)= (x−2)² +(sin(x)+1)²
b. d 2 =f(x)=(x−2)² +(sin(x)+1)²

Answer 1

The derivative of both functions is equal.

Step-by-step explanation:

To find the derivative of the given functions, we can use the chain rule and the power rule. Let's start with function a. The derivative of (x - 2)^2 is 2(x - 2), and the derivative of (sin(x) + 1)^2 is 2(sin(x) + 1)cos(x). Now, let's find the derivative of function b. It follows the same steps as function a. The derivative of (x - 2)^2 is 2(x - 2), and the derivative of (sin(x) + 1)^2 is 2(sin(x) + 1)cos(x). Therefore, the derivatives of both functions are equal.