82.6k views
1 vote
Linear Factors amposition for (1)/(x² -5x+6)

1 Answer

1 vote

Final answer:

The student's question involves decomposing the function 1/(x² -5x+6) into linear factors by first factoring the quadratic denominator, then using partial fractions to find the coefficients that will simplify the expression.

Step-by-step explanation:

The student has asked about the Linear Factors Decomposition of the function f(x) = 1/(x² -5x+6). To find the linear factors, we first need to factor the quadratic denominator. The denominator factors into (x-2)(x-3), allowing us to decompose the function into partial fractions as follows:

  • Set up the equation ²1/(x-2)(x-3)² = A/(x-2) + B/(x-3)
  • Find the values of A and B by multiplying both sides by the denominator and setting up equations for x that eliminate one of the denominators at a time.
  • Solve the system of equations to find A and B.

Once A and B are found, the original function can be expressed as the sum of two simpler fractions which are easier to integrate or differentiate if required.

User Peter Staev
by
8.0k points

No related questions found