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Linear Factors amposition for (1)/(x² -5x+6)

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Final answer:

The student's question involves decomposing the function 1/(x² -5x+6) into linear factors by first factoring the quadratic denominator, then using partial fractions to find the coefficients that will simplify the expression.

Step-by-step explanation:

The student has asked about the Linear Factors Decomposition of the function f(x) = 1/(x² -5x+6). To find the linear factors, we first need to factor the quadratic denominator. The denominator factors into (x-2)(x-3), allowing us to decompose the function into partial fractions as follows:

  • Set up the equation ²1/(x-2)(x-3)² = A/(x-2) + B/(x-3)
  • Find the values of A and B by multiplying both sides by the denominator and setting up equations for x that eliminate one of the denominators at a time.
  • Solve the system of equations to find A and B.

Once A and B are found, the original function can be expressed as the sum of two simpler fractions which are easier to integrate or differentiate if required.

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