Final answer:
To solve the quadratic equation 2x²+3x−2=0, we can use the quadratic formula. The solutions, ordered from least to greatest, are approximately -1.5 and 0.5.
Step-by-step explanation:
To solve the quadratic equation 2x²+3x−2=0, we can use the quadratic formula: x = (-b ± √(b²-4ac)) / (2a)
Here, a = 2, b = 3, and c = -2.
Substituting the values into the formula, we get:
x = (-3 ± √(3²-4(2)(-2))) / (2(2))
Simplifying further, we have:
x = (-3 ± √(9+16)) / 4
x = (-3 ± √25) / 4
So, the solutions to the quadratic equation 2x²+3x−2=0, ordered from least to greatest, are:
x = (-3 - √25) / 4 ≈ -1.5
x = (-3 + √25) / 4 ≈ 0.5