121k views
1 vote
Divide the polynomial (2x³+2x²-6x+18) ÷ (x+3) using long division. What is the correct quotient for this division?

1 Answer

3 votes

Final answer:

The correct quotient when dividing the polynomial (2x³ + 2x² - 6x + 18) by (x + 3) using long division is 2x² - 4x + 6, with a remainder of 0, meaning the division is exact.

Step-by-step explanation:

To divide the polynomial (2x³ + 2x² - 6x + 18) by (x + 3) using long division, begin by setting up the division similar to how you would with numbers.

  1. Divide the first term of the numerator, 2x³, by the first term of the denominator, x, to get the first term of the quotient, 2x².
  2. Multiply the entire denominator (x + 3) by the first term of the quotient (2x²) and subtract this from the original polynomial.
  3. Bring down the next term from the original polynomial and repeat the process until all terms have been accounted for.
  4. If there is a remainder after all terms have been divided, it can be expressed as a fraction of the original divisor.

Conducting the long division process, we find that the correct quotient is:

2x² - 4x + 6and the remainder is 0, so the division is exact.

User Arets Paeglis
by
8.6k points