Final answer:
The curve 7x+3y²−y=3 has a vertical tangent line at the point (3/7, 0).
Step-by-step explanation:
To determine if the curve 7x+3y²−y=3 has a vertical tangent line, we need to check if the derivative of y with respect to x is undefined at any point on the curve. The derivative of y with respect to x is given by:
dy/dx = -(7/6x + 1/(2y))
A vertical tangent line occurs when the derivative is undefined. To find when the derivative is undefined, we set the denominator equal to zero:
2y = 0
y = 0
Substituting y = 0 back into the original equation, we get:
7x - y = 3
7x - 0 = 3
7x = 3
x = 3/7
So, the curve has a vertical tangent line at the point (3/7, 0).
Therefore, the answer is: A) Yes, it has a vertical tangent line.