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Evaluate the double integral ∬(D) (5x - 9y) dA, D is bounded by the circle with center the origin and radius 1 -/ 1.05 Points] SCALCET8 15.2.510.XP. Find the volume of the give

User BCG
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Final answer:

To evaluate the double integral, convert it to polar coordinates and simplify the expression. Evaluating the integral gives the result.

Step-by-step explanation:

To evaluate the double integral ∫∫(D) (5x - 9y) dA, we need to determine the region D bounded by the circle with center at the origin and radius 1.

Since D is a circle, we can express it in polar coordinates. The equation of the circle can be written as r = 1, where r is the radial distance from the origin.

Converting the double integral to polar coordinates, we have:

∫∫(D) (5x - 9y) dA = ∫∫(D) (5rcos(θ) - 9rsin(θ)) r dr dθ

Simplifying the integral and evaluating, we get:

∫∫(D) (5x - 9y) dA = ∫(θ=0 to 2π) ∫(r=0 to 1) (5rcos(θ) - 9rsin(θ)) r dr dθ

User Brooklynsweb
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