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The volume is equal to the integral from 0 to 3 of sqrt(36 - x² ) dx.

User May Oakes
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Final answer:

To find the volume of the region under the curve y = √(36 - x²) from x = 0 to x = 3, set up an integral using the formula for finding the volume of a solid of revolution: V = ∫03 π(f(x))² dx. Evaluate the integral to find the volume.

Step-by-step explanation:

The given question asks for the volume of the region under the curve y = √(36 - x²) from x = 0 to x = 3. To find this volume, we can set up an integral using the formula for finding the volume of a solid of revolution. The integral would be:

V = ∫03 π(f(x))² dx

where f(x) is the function under the curve. In this case, f(x) = √(36 - x²).
Evaluating this integral will give the volume of the region.

User Ssbssa
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