33.9k views
1 vote
A fluid moves through a tube of length 1 meter and radius r=0.006±0.00015 meters under a pressure p=2.10^5±1000 pascals, at a rate v=0.75*10^(-9) m^3 per ?

1 Answer

3 votes

Final Answer:

The volume flow rate of the fluid through the tube is 1.35*10^-6 ± 2.25*10^-9 m^3/s.

Step-by-step explanation:

The volume flow rate, Q, of a fluid through a tube can be calculated using the formula:

Q = v * A

where v is the velocity of the fluid and A is the cross-sectional area of the tube. In our case, we know the velocity, v, which is given as 0.75*10^-9 m^3/s, and we can calculate the cross-sectional area, A, using the radius, r:

A = πr^2

Substituting our values for v and r into the formula for Q, we get:

Q = 0.75*10^-9 * π * (0.006 ± 0.00015)^2 m^3/s

Simplifying this expression and rounding to three significant figures, we obtain our final answer: Q = 1.35*10^-6 ± 2.25*10^-9 m^3/s. The uncertainty in Q is calculated using the propagation of uncertainty formula:

δQ = sqrt(δv^2 + v^2 * δA^2)

where δv and δA are the uncertainties in velocity and cross-sectional area, respectively. Using our given uncertainties for v and r, we can calculate δA as follows:

δA = 2 * r * δr = 2 * (0.006 ± 0.00015) * (0.00015) m^2/s

Substituting this into the formula for δQ and simplifying, we get:

δQ = sqrt(δv^2 + v^2 * (4 * r * δr)^2) = sqrt(10^4 * (4 * (6*10^-6) * (1.5*10^-6))^2) m^3/s = 2.25*10^-9 m^3/s.

User Jeppz
by
7.7k points