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If the partial fraction expansion of -2x + 63 / ((x - 4)(x + 7)) is A / (x - 4) + B / (x + 7), then A = ?

User Drhyde
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1 Answer

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Final answer:

To find the value of A in the partial fraction expansion of -2x + 63 / ((x - 4)(x + 7)) = A / (x - 4) + B / (x + 7), we cleared the denominators and solved for A by setting x to 4, resulting in A = 5.

Step-by-step explanation:

The student has provided a partial fraction expansion problem, which is a concept in algebra where a complex fraction is broken down into simpler fractions that add up to the original fraction. To find the value of A in the partial fraction expansion of -2x + 63 / ((x - 4)(x + 7)) that is expressed as A / (x - 4) + B / (x + 7), we must clear the denominators and solve for A.

We begin by multiplying both sides of the equation by the common denominator (x - 4)(x + 7) to eliminate the fractions:

-2x + 63 = A(x + 7) + B(x - 4)

To solve for A, we can substitute x = 4 into the equation since this will cause the B term to drop out (because B(x - 4) will be zero when x = 4):

-2(4) + 63 = A(4 + 7)

-8 + 63 = A(11)

55 = A(11)

Divide both sides by 11 to get A:

A = 5

Therefore, the value of A in the given partial fraction expansion is 5.

User Davideas
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