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Consider the curve defined by y = (x⁶)/8 + (1/(12x⁴)) from x = 1 to x = 4. The length of this curve is L = ∫[1 to 4] √(1 + (f'(x))²) dx, where f'(x) is the derivative of y with respect to x.

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Final answer:

To find the curve's length defined by y = (x⁶)/8 + (1/(12x⁴)), we need to calculate its derivative, square it, add 1, and evaluate the definite integral of the square root of this sum from x = 1 to x = 4.

Step-by-step explanation:

The student's question relates to finding the length of a curve defined by y = (x⁶)/8 + (1/(12x⁴)) between x = 1 and x = 4. This involves calculating the integral of the square root of 1 plus the derivative of the function squared, indicated as L = ∫[1 to 4] √(1 + (f'(x))²) dx. To proceed, we need to find the derivative of the function, f'(x), then substitute it into the integrand to evaluate the arc length.

Firstly, we compute f'(x) as follows:

  • Take the derivative of the function y with respect to x.
  • Simplify and square the derivative.
  • Add 1 to the squared derivative as per the formula for the arc length.
  • Take the square root of the entire expression to get the integrand.
  • Finally, integrate this expression from x = 1 to x = 4 to find the arc length L.

This process will yield the exact length of the curve within the given bounds.

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