Final answer:
To solve the quadratic equation -3x²-16=-3x in standard form, rearrange the equation into the form ax²+bx+c=0. Then, use the quadratic formula to find the solutions. In this case, there are no real solutions.
Step-by-step explanation:
To solve the quadratic equation -3x²-16=-3x in standard form, we need to rearrange the equation in the form ax²+bx+c=0, where a, b, and c are constants. In this case, a = -3, b = 3, and c = -16. Now we can use the quadratic formula to find the solutions:
x = (-b ± √(b² - 4ac)) / (2a)
Plugging in the values, we get:
x = (-(-3) ± √((-3)² - 4(-3)(-16))) / (2(-3))
x = (3 ± √(9 - 192)) / -6
x = (3 ± √(-183)) / -6
Since the discriminant (b² - 4ac) is negative, there are no real solutions for the given quadratic equation.