Final answer:
The real zeros of the function f(x)=6(x-4)(x+7)(x-3) are x=4, x=-7, and x=3, found by setting each factor equal to zero.
Step-by-step explanation:
The student's question asks to find the real zeros of the function f(x)=6(x-4)(x+7)(x-3). The real zeros of a polynomial function are the values of x for which the function equals zero. These would be the x-values that make each factor of the polynomial equal to zero.
To find the zeros, we set each factor equal to zero and solve for x:
- x - 4 = 0 → x = 4
- x + 7 = 0 → x = -7
- x - 3 = 0 → x = 3
Therefore, the real zeros of the function are x = 4, x = -7, and x = 3.