2.0k views
0 votes
Multiply the following polynomials: (2r+2)(6r²+3r-1). What is the result, and what is the coefficient of the r term in the product?

User Balajiboss
by
7.0k points

1 Answer

3 votes

Final answer:

To multiply the polynomials (2r+2)(6r²+3r-1), distribute each term of the first polynomial to each term of the second polynomial, simplify, and combine like terms. The coefficient of the r term in the product is 4.

Step-by-step explanation:

To multiply the polynomials (2r+2)(6r²+3r-1), we use the distributive property. We multiply each term of the first polynomial by each term of the second polynomial. This gives us:
(2r)(6r²) + (2r)(3r) + (2r)(-1) + (2)(6r²) + (2)(3r) + (2)(-1).

Simplifying the expression gives us:
12r³ + 6r² + -2r + 12r² + 6r - 2.

Combining like terms, we get:
12r³ + 18r² + 4r - 2.

The coefficient of the r term in the product is 4.

User Sergio Pardo
by
7.9k points