Final answer:
The 'squared' one-dimensional matrix A², obtained by squaring each individual element of A [0,-3,-6,-2], is [0, 9, 36, 4].
Step-by-step explanation:
The question involves finding the square of a matrix, denoted as A². However, from the provided matrix A, which is [0,-3,-6,-2], it appears to be a one-dimensional array, not a traditional square or rectangular two-dimensional matrix. To square this matrix in the conventional sense, we would need a square matrix with an equal number of rows and columns. That said, if we were to multiply this array by itself element-wise (Hadamard product), the resulting elements of the 'squared' one-dimensional matrix A² would be calculated as the square of each individual element in A.
If we follow this non-standard element-wise squaring approach:
- The element 0 squared is 0.
- The element -3 squared is 9.
- The element -6 squared is 36.
- The element -2 squared is 4.
Consequently, the new 'squared' one-dimensional matrix A², given by squaring each individual element, would be [0, 9, 36, 4].