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To find the derivative of the function f(x)=xex²(x2+1)10 using logarithmic differentiation,

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Final answer:

To find the derivative of f(x)=xex²(x^2+1)^10 using logarithmic differentiation, you can follow these steps: Step 1: Take the natural logarithm of both sides of the equation. Step 2: Use the properties of logarithms to simplify the expression. Step 3: Differentiate both sides of the equation with respect to x.

Step-by-step explanation:

Derivative of f(x)=xex²(x^2+1)^10 using logarithmic differentiation:

Step 1: Take the natural logarithm of both sides of the equation to simplify the expression:

ln(f(x)) = ln(xex²(x^2+1)^10)

Step 2: Use the properties of logarithms to simplify further:

ln(f(x)) = ln(x) + ln(ex²) + ln((x^2+1)^10)

Step 3: Differentiate both sides of the equation with respect to x:

(1/f(x)) * f'(x) = 1/x + 2x + 10(x^2+1) * (2x/(x^2+1))

Step 4: Solve for f'(x) by multiplying both sides by f(x):

f'(x) = f(x) * (1/x + 2x + 20x(x^2+1)/(x^2+1))

Step 5: Substitute f(x) back in:

f'(x) = xex²(x^2+1)^10 * (1/x + 2x + 20x(x^2+1)/(x^2+1))

Step 6: Simplify the expression:

f'(x) = xex²(x^2+1)^10 * (1/x + 2x + 20x)

Step 7: Further simplify and combine like terms:

f'(x) = xex²(x^2+1)^10 * (1/x + 22x)

Therefore, the derivative of f(x)=xex²(x^2+1)^10 using logarithmic differentiation is f'(x) = xex²(x^2+1)^10 * (1/x + 22x).

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