Question

Lowing fractions and express in fully (7)/(9x)+(1)/(3x)

Answer 1

To add the fractions (7)/(9x) and (1)/(3x), find a common denominator, which is 9x. Rewrite the second fraction as (3)/(9x) and then add the numerators to get the sum (10)/(9x).

Step-by-step explanation:

The question involves adding two fractional algebraic expressions, (7)/(9x) and (1)/(3x). To add fractions, we must have a common denominator. In this case, the lowest common denominator for 9x and 3x is 9x, as 9x is a multiple of 3x.

First, we rewrite the second fraction with the common denominator:

(1)/(3x) becomes (3)/(9x) when we multiply both the numerator and the denominator by 3.

Now we have:

(7)/(9x) + (3)/(9x)

Since the denominators are the same, we can add the numerators:

7 + 3 = 10

So the sum of the two fractions is (10)/(9x).