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Let's evaluate the given integrals:

(a) ∫34x−31dx
Let's find the values and limits as requested:

User Wharbio
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1 Answer

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Final answer:

The evaluate the integral ∫3(4x−3)dx is (3/2) * (4x^2 - 3x) + C.

Step-by-step explanation:

To evaluate the integral ∫3(4x−3)dx, we can use the power rule of integration.

According to this rule, the integral of x^n with respect to x is equal to (1/(n+1)) * x^(n+1) + C, where C is the constant of integration.

Applying this rule to the given integral, we have:

∫3(4x−3)dx = (3/2) * (4x^2 - 3x) + C

Therefore, the value of the integral is (3/2) * (4x^2 - 3x) + C.

User Quantka
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