Final Answer:
The real square roots of -(9)/(16) are ±(3)/(4).
Step-by-step explanation:
Calculation to find the real square roots of -(9)/(16).
Given expression: -(9)/(16)
To find the square root, we use the fact that the square root of a product is the product of the square roots:
![\[ √(-(9)/(16)) = √((-1) \cdot (9/16)) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/bxqvs19mo0j7mocbjrm77dqjefly5qsda0.png)
Now, we can break it down further:
![\[ √(-(9)/(16)) = √(-1) \cdot √((9/16)) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/u6go50lal4d4dg50ne4tosmkcdgb7eg5ph.png)
The square root of -1 is denoted by 'i' in complex numbers. Therefore:
![\[ √(-(9)/(16)) = i \cdot (√(9)/√(16)) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/a2zknl52j3bjb69sjk6k0wxojnwqzx8ljx.png)
Now, simplify the square roots:
![\[ √(-(9)/(16)) = i \cdot (3/4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v74mj7oge6qwjtmew6otukeapbgpc6mjuj.png)
So, the complex square root of -(9)/(16) is
However, we are looking for real square roots, which means we need to consider both positive and negative values.
![\[ √(-(9)/(16)) = i \cdot (3/4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v74mj7oge6qwjtmew6otukeapbgpc6mjuj.png)
Therefore, the final real square roots are:
![\[ \pm i \cdot (3/4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/i2rdlo34k53d51ghvydumthsn2d27yiu1j.png)
In a real number context, 'i' represents the imaginary unit, but since we are looking for real square roots, we discard the 'i'. Thus, the final answer is:
![\[ \pm (3/4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/urqfi0ixxk8277v0l3oo2g0ro5v25qn64e.png)
This means that both ( (3/4) ) and ( -(3/4) ) are the real square roots of -(9)/(16), as squaring either of them results in the original expression.