Question

How would you make a 6% Hetastarch, .9% normal saline solution
for the
500mL

Answer 1

To make a 6% Hetastarch, 0.9% normal saline solution, you would need 300 mL of a 10% Hetastarch stock solution and 200 mL of 0.9% normal saline solution.

Step-by-step explanation:

To prepare a 6% Hetastarch, 0.9% normal saline solution for 500 mL, you would need to calculate the mass of Hetastarch and sodium chloride (NaCl) required to achieve the desired concentrations in the final volume of the solution. To make a 6% Hetastarch, 0.9% normal saline solution, you would need to know the concentration of Hetastarch stock solution you have. Let's assume you have a 10% Hetastarch stock solution. To prepare a 500 mL solution, you can use the formula:

Volume of Hetastarch stock solution (in mL) = (Desired Hetastarch concentration / Hetastarch stock solution concentration) * final volume of solution

Volume of Hetastarch stock solution = (6% / 10%) * 500 mL = 0.6 * 500 mL = 300 mL

Therefore, you would need 300 mL of the 10% Hetastarch stock solution and 200 mL of 0.9% normal saline solution to make a 6% Hetastarch, 0.9% normal saline solution.