Question

Find a unit vector parallel to =⟨−3,−2,−3⟩.
= ?

Answer 1

A unit vector parallel to the vector <-3, -2, -3> is found by dividing each component by the vector's magnitude, resulting in <-3/√22, -2/√22, -3/√22>.

Step-by-step explanation:

To find a unit vector parallel to <-3, -2, -3>, you need to divide each component of the vector by its magnitude. First, calculate the magnitude of the vector <-3, -2, -3> which is the square root of the sum of the squares of its components:

√((-3)² + (-2)² + (-3)²) = √(9 + 4 + 9) = √22

Now, by dividing each component by √22, you get the unit vector:

<-3/√22, -2/√22, -3/√22>

This is the unit vector parallel to the original vector.