Final answer:
To find the original function d(t) from the given derivative expression d'(t) = 5cos²(t), we need to perform the reverse operation, which is integration. We can integrate 5cos²(t) to find d(t).
Step-by-step explanation:
To find the original function d(t) from the given derivative expression d'(t) = 5cos²(t), we need to perform the reverse operation, which is integration. We can integrate 5cos²(t) to find d(t).
- Using the trigonometric identity cos²(t) = 1/2 + 1/2cos(2t) to rewrite the expression, we have d'(t) = 5(1/2 + 1/2cos(2t)).
- Integrating each term separately, we get d(t) = 5t/2 + 5/4sin(2t) + C, where C is the constant of integration.
Therefore, the original function d(t) is d(t) = 5t/2 + 5/4sin(2t) + C, where C is a constant.